(5x^2)/(x-8)(x+3)=0

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Solution for (5x^2)/(x-8)(x+3)=0 equation: 



(5x^2)/(x-8)(x+3)=0



Domain of the equation: (x-8)(x+3)!=0

We move all terms containing x to the left, all other terms to the right

x-8)(x!=-3

x∈R



We multiply parentheses ..

5x^2/(+x^2+3x-8x-24)=0

We multiply all the terms by the denominator


5x^2=0

a = 5; b = 0; c = 0;
Δ = b2-4ac
Δ = 02-4·5·0
Δ = 0
Delta is equal to zero, so there is only one solution to the equation

                              Stosujemy wzór:
$x=\frac{-b}{2a}=\frac{0}{10}=0$

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